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===What are the odds that dX beats dY?=== Want to know if a d6 is going to beat a d12? First, there are 72 ways this could come out (6 times 12, from the two dice), so the answer will be X/72. Next, look at it this way: If the d12 lands on a 6 or higher, then the d6 will not be higher than it. If it lands on a 5, then one of the results on the d6, the 6, would be higher than it. So that's 1/72 so far. If it lands on a 4 then there are two results, if it lands on a 1 then there are five. There's a total of 1+2+3+4+5 results that would make the d6 the higher die, 15 in total. The odds of a d6 being higher than a d12 are 15/72. d10 vs d12? That's 9+8+etc / 10*12, so 45/120. It turns out, if ''Y'' is larger than ''X'', the formula for the probability is very simple: [[File:Probability Eq10.png|x60px]]
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